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# Helpin ritz with math AuthorMessage

Chuunin Posts : 338
Join date : 2008-08-31
Age : 27
Location : Somewhere nearby  Subject: Helpin ritz with math Wed Mar 03, 2010 11:09 pm ok so one your problem you have to solve with substitutionyour given x+4y=17 and 3x-y=12so first you want to want to get one variable on either equation by itself.ex x+4y=17 = x=-4y+17, then you want to substitute that in for x in the other problem3(-4y+17)-y=12 then distribute the 3-12y+51-y=12 then get the y's alone-13y=-39 then solve for yy=3then go back and solve for x in the problem3x-(3)=123x=15x=5   Hokage Posts : 731
Join date : 2008-08-29
Age : 27
Location : Leaf Village  Subject: Re: Helpin ritz with math Thu Mar 04, 2010 4:01 am Good job. Haha._________________Hokage of the Leaf Village    Posts : 49
Join date : 2009-07-28
Age : 27  Subject: Re: Helpin ritz with math Thu Mar 04, 2010 4:23 am I would've done it using simultaneous equations to get rid of variables. Ex:x + 4y = 17 <-- multiply by -3 so you can cancel the x values when you add equations3x - y = 12=>-3x -12y = -513x - y = 12 <-- add the equations=>-13y = -39-y = -3y = 3Then, solve for x by substituting a y value in one of the equations:3x-(3)=123x=15x=5Either way works, but just to show you there are two ways of doing this   Chuunin Posts : 338
Join date : 2008-08-31
Age : 27
Location : Somewhere nearby  Subject: Re: Helpin ritz with math Thu Mar 04, 2010 3:27 pm I know thats how i would have done it but her paper said use substitution. so i showed here substitution.     Subject: Re: Helpin ritz with math   Helpin ritz with math  