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 Helpin ritz with math

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Kuroi
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PostSubject: Helpin ritz with math   Wed Mar 03, 2010 11:09 pm

ok so one your problem you have to solve with substitution

your given x+4y=17 and 3x-y=12

so first you want to want to get one variable on either equation by itself.

ex x+4y=17 = x=-4y+17, then you want to substitute that in for x in the other problem

3(-4y+17)-y=12 then distribute the 3

-12y+51-y=12 then get the y's alone

-13y=-39 then solve for y

y=3

then go back and solve for x in the problem

3x-(3)=12

3x=15

x=5
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NinjaTez
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PostSubject: Re: Helpin ritz with math   Thu Mar 04, 2010 4:01 am

Good job. Haha.

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Riketz

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PostSubject: Re: Helpin ritz with math   Thu Mar 04, 2010 4:23 am

I would've done it using simultaneous equations to get rid of variables.

Ex:

x + 4y = 17 <-- multiply by -3 so you can cancel the x values when you add equations
3x - y = 12

=>

-3x -12y = -51
3x - y = 12 <-- add the equations

=>

-13y = -39

-y = -3

y = 3

Then, solve for x by substituting a y value in one of the equations:

3x-(3)=12

3x=15

x=5


Either way works, but just to show you there are two ways of doing this
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Kuroi
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PostSubject: Re: Helpin ritz with math   Thu Mar 04, 2010 3:27 pm

I know thats how i would have done it but her paper said use substitution. so i showed here substitution.
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